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9j^2-7j-9=0
a = 9; b = -7; c = -9;
Δ = b2-4ac
Δ = -72-4·9·(-9)
Δ = 373
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$j_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{373}}{2*9}=\frac{7-\sqrt{373}}{18} $$j_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{373}}{2*9}=\frac{7+\sqrt{373}}{18} $
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